What is the probability of getting a tail and an odd number in tossing a coin and rolling a die? ✅ [Update]

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Hoàng Đại Thắng đang tìm kiếm từ khóa What is the probability of getting a tail and an odd number in tossing a coin and rolling a die? được Cập Nhật vào lúc : 2022-09-26 09:12:05 . Với phương châm chia sẻ Thủ Thuật về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi đọc nội dung bài viết vẫn ko hiểu thì hoàn toàn có thể lại phản hồi ở cuối bài để Mình lý giải và hướng dẫn lại nha.

Nội dung chính
    The correct option is C 114The possible outcomes are: (1, H, H), (1, H, T), (1, T, 1), (1, T, 2), (1, T, 3), (1, T, 4), (1, T, 5), (1, T, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, H, H), (3, H, T), (3, T, 1), (3, T, 2), (3, T, 3), (3, T, 4), (3, T, 5), (3, T, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, H, H), (5, H, T), (5, T, 1), (5, T, 2), (5, T, 3), (5, T, 4), (5, T, 5), (5, T, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) ∴ Total number of outcomes = 42 Also, the outcomes having two heads are (1, H, H), (3, H, H), (5, H, H). ∴ Number of outcomes having two heads = 3 ∴ P(getting 2 heads) =Number of favourable outcomesTotal number of outcomes=342=114 Hence, the correct answer is option c.What is the probability of getting a tails and an odd number?What is the probability of getting both a head on a coin toss and an odd number on the throw of a die?What is the probability of getting a head and a tail when a coin is tossed and a die is rolled?When a coin and die are tossed what is the probability of getting a tail on the coin and even numbers on the die?

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Solution

The correct option is C 114The possible outcomes are: (1, H, H), (1, H, T), (1, T, 1), (1, T, 2), (1, T, 3), (1, T, 4), (1, T, 5), (1, T, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, H, H), (3, H, T), (3, T, 1), (3, T, 2), (3, T, 3), (3, T, 4), (3, T, 5), (3, T, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, H, H), (5, H, T), (5, T, 1), (5, T, 2), (5, T, 3), (5, T, 4), (5, T, 5), (5, T, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) ∴ Total number of outcomes = 42 Also, the outcomes having two heads are (1, H, H), (3, H, H), (5, H, H). ∴ Number of outcomes having two heads = 3 ∴ P(getting 2 heads) =Number of favourable outcomesTotal number of outcomes=342=114 Hence, the correct answer is option c.

The probability of some sự kiện happening is a mathematical (numerical) representation of how likely it is to happen, where a probability of 1 means that an sự kiện will always happen, while a probability of 0 means that it will never happen. Classical probability problems often need to you find how often one outcome occurs versus another, and how one sự kiện happening affects the probability of future events happening. When you look all the things that may occur, the formula (just as our coin flip probability formula) states that

probability = (no. of successful results) / (no. of all possible results).

Take a die roll as an example. If you have a standard, 6-face die, then there are six possible outcomes, namely the numbers from 1 to 6. If it is a fair die, then the likelihood of each of these results is the same, i.e., 1 in 6 or 1 / 6. Therefore, the probability of obtaining 6 when you roll the die is 1 / 6. The probability is the same for 3. Or 2. You get the drill. If you don't believe me, take a dice and roll it a few times and note the results. Remember that the more times you repeat an experiment, the more trustworthy the results. So go on, roll it, say, a thousand times. We'll be waiting here until you get back to tell us we've been right all along.

But what if you repeat an experiment a hundred times and want to find the odds that you'll obtain a fixed result least 20 times?

Let's look another example. Say that you're a teenager straight out of middle school and decide that you want to meet the love of your life this year. More specifically, you want to ask ten girls out and go on a date with only four of them. One of those has got to be the one, right? The first thing you have to do in this situation is look in the mirror and rate how likely a girl is to agree to go out with you when you start talking to her. If you have problems with assessing your looks fairly, go downstairs and let your grandma tell you what a handsome, young gentleman you are. So a solid 9 / 10 then.

As you only want to go on four dates, that means you only want four of your romance attempts to succeed. This has an outcome of 9 / 10. This means that you want the other six girls to reject you, which, based on your good looks, has only a 1 / 10 change of happening (The sum of all events happening is always equal to 1, so we get this number by subtracting 9 / 10 from 1). If you multiply the probability of each sự kiện by itself the number of times you want it to occur, you get the chance that your scenario will come true. In this case, your odds are 210 * (9 / 10)4 * (1 / 10)6 = 0.000137781, where the 210 comes from the number of possible fours of girls among the ten that would agree. Not very likely to happen, is it? Maybe you should try being less beautiful!

What is the probability of getting a tails and an odd number?


The probability of getting tails an odd number of times is 1/2 .

What is the probability of getting both a head on a coin toss and an odd number on the throw of a die?

The probability of getting a head on the coin and an odd number on the die =21×63=41.

What is the probability of getting a head and a tail when a coin is tossed and a die is rolled?

When we flip a coin there is always a probability to get a head or a tail is 50 percent. Suppose a coin tossed then we get two possible outcomes either a 'head' (H) or a 'tail' (T), and it is impossible to predict whether the result of a toss will be a 'head' or 'tail'. (i) If the favourable outcome is head (H).

When a coin and die are tossed what is the probability of getting a tail on the coin and even numbers on the die?

The coin is fair, the probabilities of getting a head and a tail are equal to 12 . The probability of getting an even number on a die is 36=12 because among 6 results there are 3 even numbers.

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